Integrand size = 24, antiderivative size = 80 \[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=\frac {i (a-i a \tan (c+d x))^4}{a^5 d}-\frac {4 i (a-i a \tan (c+d x))^5}{5 a^6 d}+\frac {i (a-i a \tan (c+d x))^6}{6 a^7 d} \]
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Time = 0.08 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {3568, 45} \[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=\frac {i (a-i a \tan (c+d x))^6}{6 a^7 d}-\frac {4 i (a-i a \tan (c+d x))^5}{5 a^6 d}+\frac {i (a-i a \tan (c+d x))^4}{a^5 d} \]
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Rule 45
Rule 3568
Rubi steps \begin{align*} \text {integral}& = -\frac {i \text {Subst}\left (\int (a-x)^3 (a+x)^2 \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = -\frac {i \text {Subst}\left (\int \left (4 a^2 (a-x)^3-4 a (a-x)^4+(a-x)^5\right ) \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = \frac {i (a-i a \tan (c+d x))^4}{a^5 d}-\frac {4 i (a-i a \tan (c+d x))^5}{5 a^6 d}+\frac {i (a-i a \tan (c+d x))^6}{6 a^7 d} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.58 \[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=-\frac {i (i+\tan (c+d x))^4 \left (-11-14 i \tan (c+d x)+5 \tan ^2(c+d x)\right )}{30 a d} \]
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Time = 0.37 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.59
method | result | size |
risch | \(\frac {16 i \left (15 \,{\mathrm e}^{4 i \left (d x +c \right )}+6 \,{\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{15 d a \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{6}}\) | \(47\) |
derivativedivides | \(-\frac {-\tan \left (d x +c \right )+\frac {i \left (\tan ^{6}\left (d x +c \right )\right )}{6}-\frac {\left (\tan ^{5}\left (d x +c \right )\right )}{5}+\frac {i \left (\tan ^{4}\left (d x +c \right )\right )}{2}-\frac {2 \left (\tan ^{3}\left (d x +c \right )\right )}{3}+\frac {i \left (\tan ^{2}\left (d x +c \right )\right )}{2}}{a d}\) | \(71\) |
default | \(-\frac {-\tan \left (d x +c \right )+\frac {i \left (\tan ^{6}\left (d x +c \right )\right )}{6}-\frac {\left (\tan ^{5}\left (d x +c \right )\right )}{5}+\frac {i \left (\tan ^{4}\left (d x +c \right )\right )}{2}-\frac {2 \left (\tan ^{3}\left (d x +c \right )\right )}{3}+\frac {i \left (\tan ^{2}\left (d x +c \right )\right )}{2}}{a d}\) | \(71\) |
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Time = 0.23 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.36 \[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=-\frac {16 \, {\left (-15 i \, e^{\left (4 i \, d x + 4 i \, c\right )} - 6 i \, e^{\left (2 i \, d x + 2 i \, c\right )} - i\right )}}{15 \, {\left (a d e^{\left (12 i \, d x + 12 i \, c\right )} + 6 \, a d e^{\left (10 i \, d x + 10 i \, c\right )} + 15 \, a d e^{\left (8 i \, d x + 8 i \, c\right )} + 20 \, a d e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, a d e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, a d e^{\left (2 i \, d x + 2 i \, c\right )} + a d\right )}} \]
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\[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=- \frac {i \int \frac {\sec ^{8}{\left (c + d x \right )}}{\tan {\left (c + d x \right )} - i}\, dx}{a} \]
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Time = 0.26 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.84 \[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=\frac {-5 i \, \tan \left (d x + c\right )^{6} + 6 \, \tan \left (d x + c\right )^{5} - 15 i \, \tan \left (d x + c\right )^{4} + 20 \, \tan \left (d x + c\right )^{3} - 15 i \, \tan \left (d x + c\right )^{2} + 30 \, \tan \left (d x + c\right )}{30 \, a d} \]
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Time = 0.39 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.84 \[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=-\frac {5 i \, \tan \left (d x + c\right )^{6} - 6 \, \tan \left (d x + c\right )^{5} + 15 i \, \tan \left (d x + c\right )^{4} - 20 \, \tan \left (d x + c\right )^{3} + 15 i \, \tan \left (d x + c\right )^{2} - 30 \, \tan \left (d x + c\right )}{30 \, a d} \]
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Time = 3.94 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.42 \[ \int \frac {\sec ^8(c+d x)}{a+i a \tan (c+d x)} \, dx=\frac {\sin \left (c+d\,x\right )\,\left (30\,{\cos \left (c+d\,x\right )}^5-{\cos \left (c+d\,x\right )}^4\,\sin \left (c+d\,x\right )\,15{}\mathrm {i}+20\,{\cos \left (c+d\,x\right )}^3\,{\sin \left (c+d\,x\right )}^2-{\cos \left (c+d\,x\right )}^2\,{\sin \left (c+d\,x\right )}^3\,15{}\mathrm {i}+6\,\cos \left (c+d\,x\right )\,{\sin \left (c+d\,x\right )}^4-{\sin \left (c+d\,x\right )}^5\,5{}\mathrm {i}\right )}{30\,a\,d\,{\cos \left (c+d\,x\right )}^6} \]
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